Horizontal Trajectory
A horizontal trajectory
problem is a two-part problem because when an object is thrown it covers
a horizontal distance due to initial velocity, and also behaves as a
free falling object due to gravity pulling the object down. The object
therefore has two velocities, a downward and horizontal velocity. Visit
the following link to view a graphic of this situation:
http://hyperphysics.phy-astr.gsu.edu/hbase/traj.html#tra11
The downward velocity of the
object is not constant because of gravity; therefore time in the air and
velocity before it hits the ground can be calculated as if it was a free
falling problem.
In a horizontal trajectory
problem, air friction is neglected therefore horizontal velocity is
constant. This concept allows us to calculate the total range covered by
the object thrown with the simple equation:
R = vxot
where R = range
vxo
= initial velocity thrown
t = time
in the air
Procedures for a Horizontal
trajectory problem
1)
Calculate time in the air: t =
2)
Calculate total range: R = vot
3)
Calculate downward velocity: vy = at
4)
Calculate velocity before it hits the ground: v = sqrt(vo2
+ vy2)
Visit a horizontal launch online simulator to view a graphic and
calculations of this situation:
http://hyperphysics.phy-astr.gsu.edu/hbase/traj.html#tra11
Procedures
1)
Set an initial launch velocity and height.
2)
Select equations to calculate range and time.
Assessment
1)
Email complete solutions to the following problems to the
instructor. Use the link above to compare solutions.
a)
A rock is thrown from the top of a cliff 50 m above ground with
an initial velocity of 15 m/s. What is the time spent in the air and the
range achieved? What was the final velocity before it hits the ground?
b)
At what velocity must an object be thrown to cover a range of 20
m and from a height of 10 m?
2)
Using the horizontal launch simulator link above, design 2 word
problems each with different initial conditions. Through Email, trade
problems with a classmate to solve. Submit all final solutions to the
instructor.